The copper complex [Cu(N(py)3)2(CH3CN)2][SO3CF3]2, N(py)3 = 2,2′,2″-tripyridylamine, can be prepared by the reaction of Cu(SO3CF3)2 with N(py)3 in acetonitrile. The complex Cu(N(py)3)2(SO3CF3)2 can be prepared from Cu(SO3CF3)2 and N(py)3 in methanol or by recrystallizing the bis(acetonitrile) complex from acetone/ether. The bis(acetonitrile) complex crystallizes in the monoclinic space group C2h5-P21/n with two molecules in a unit cell of dimensions a = 11.825 (2) Å, b = 14.774 (3) Å, c = 11.516 (2) Å, and β = 97.699 (4)°. Least-squares refinement of the 193 variables led to a value of the conventional R index (on F) of 0.070 for 1669 reflections having Fo2 > 3σ(Fo2). The geometry about the cupric ion is tetragonally distorted octahedral (crystallographically imposed symmetry 1̄) with two pyridyl rings from each bidentate N(py)3 ligand defining the equatorial coordination. The Cu(II) ion and four nitrogen atoms are rigorously coplanar, with an average Cu-N distance of 2.020 (3) Å. The acetonitrile ligands occupy axial ligation positions with a Cu-N distance of 2.526 (8) Å. The above complexes have been studied by infrared, optical, and EPR spectroscopy. The vibrational spectroscopic results in the N(py)3 and SO3CF3 skeletal regions are in accord with bidentate N(py)3 coordination in both compounds. For Cu(N(py)3)2(SO3CF3)2, axial triflate coordination is indicated. The optical and EPR spectral data are also in accord with these structural conclusions. For [Cu(N(py)3)2(CH3CN)2][SO3CF3]2, the 14N superhyperfine coupling shows the pyridyl and acetonitrile donors to be magnetically indistinguishable.
|Original language||English (US)|
|Number of pages||9|
|State||Published - 1982|
ASJC Scopus subject areas
- Physical and Theoretical Chemistry
- Inorganic Chemistry